If cos theta = 4 then what is square of 3 sin theta -5 tan theta
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(3 sin A - 5 sin A/cos A)²
(sin A ( 3 - 5/cos A))²
(sin A (3 - 5/4))²
(sin A * 7/4)²
sin²A - 49/16
(sin A ( 3 - 5/cos A))²
(sin A (3 - 5/4))²
(sin A * 7/4)²
sin²A - 49/16
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