Question

if cos theta = 7/25 , find the value of all T-ratios of theta

Answer 1

Hi friend,

Here's your answer,

cosθ=7/25
Therefore,
Base=7cm
Hypotenuse=25cm

By Pythagoras Theorem,
h²=p²+b²
p²=h²-b²
p²=25²-7²=625-49
p=√576=24cm

Perpendicular=24cm

sinθ=p/h= 24/25

cosθ= 7/25 [given]

tanθ=p/b= 24/7

cosecθ= 25/24 [1/sinθ]

secθ= 25/7 [1/cosθ]

cotθ= 7/24 [1/tanθ]

Hope it helps!!!!

#yashankΠsingh

Answer 2

Answer:

sin theta =24/25

tan theta =24/7

sec theta =25/7

cot theta = 7/24

cosec theta =25/24

Step-by-step explanation:

cos theta =7/25 (given)

Draw a right angle triangle ABC, ∠B = 90° and ∠A = theta

we know that cos theta = base / hypotenuse =7/25

AB= 7

AC= 25

Using Pythagoras Theorem find BC

(AC)^2 =(AB)^2 + (BC)^2

(25)^2 = (7)^2 + (BC)^2

625 - 49 = 576

(BC)^2= 576

BC = ²√576

BC = 24

sin theta = BC/AC =24/25

tan theta = BC/AB =24/7

sec theta = 1 / cos theta = 25/7

cot theta = 1/ tan theta = 7/24

cosec theta = 1/ sin theta = 25 /24

#SPJ2