If cos theta =7/25 find the value of cosec theta and cot theta
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given cos∅ = 7/25
consider any right angle ∆ABC
we know that cos∅ = base/hypotenuse
therefore BC = 7 and AC = 25
by Pythagoras theorem, we get
=> AC² = AB² + BC²
=> 25² = AB² + 7²
=> 625 = AB² + 49
=> 625 - 49 = AB²
=> 576 = AB²
=> AB = √576
=> AB = 24
therefore perpendicular = 24
now we can easily find the value of cosec∅ and cot∅
cosec∅ = hypotenuse/perpendicular
= 24/25
cot∅ = base/perpendicular
= 7/24
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