Question

if cos theta = 8/17 , find sin theta

Answer 1

Let theta be A

sin^2 A = 1 - cos^2 A

sin^2 A = 1 - ( 8/17 )^2

sin^2 A = 1 - 64/289

sin^2 A = 289 - 64 /289

sin^2 A = 225 / 289

sin A = root 225/289

sin A = 15/17

so sin theta = 15/17

Answer 2

cos teta =8/17
hypotenuse = 17
adjacent side = 8
opposite side = ✓17^2- 8^2 = ✓225= 15
sin teta = opposite/hypotenuse
= 15/17
hence sin teta is 15/17