Question

If cos theta= 9\12,then find the value of sin theta+ cos theta/ sin theta- cos theta+ sec theta+ cosec theta/sec theta- cosec theta​

Answer 1

Answer:

Step-by-step explanation:

by using right angle triangle sinθ=sqrt(63) /12

cosecθ=1/sinθ=12/sqrt(63)

secθ=1/cosθ=12/9

(sinθ+cosθ)/(sinθ-cosθ) + (secθ+cosecθ)/(secθ-cosecθ)

by substituting value we get

(sqrt(63)+9)/(sqrt(63)-9) + (108+12*sqrt(63))/(108-12*sqrt(63))

hope so you understand the solution