Question

If cos theta=a/b find 1+tan^2 theta

Answer 1

Answer:

1+Tan²θ=$\frac{a^2}{b^2}$

Step-by-step explanation:

Given:-

Cosθ=a/b⇒ Cosθ=Base/Hypotenuse

a=Base and b=Hypotenuse

To Find:-

1+Tan²θ

Formula Applied:-

1+Tan²θ=Sec²θ

Cosθ=1/Secθ

Solution:-

Cos²θ=1/Sec²θ

1+Tan²θ=Sec²θ

1+Tan²θ=(a/b)²

1+Tan²θ=$\frac{a^2}{b^2}$