Question

if cos theta = a/b,find tan theta + sec theta​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Step-by-step explanation:

1. As we know that cosФ = (adjacent / hypotenuse).
2. as we will put the value of cos Ф in identity $cos^{2}$Ф + $sin^{2}$Ф = 1, then we obtain the value of sin Ф as  [($\sqrt{b^{2}-a^{2} }$) /b ] .
3. so, now tanФ is $\frac{sin}{cos}$ Ф so by putting the value of cos and sin Ф we get the value of tan Ф i.e.,  [( $\sqrt{b^{2}-a^{2} }$ )/a ] .
4. secФ is converse of cos Ф by putting the value we will get our equation ready.
5. we get that [($\sqrt{b^{2}-a^{2} }$) / a]  + $\frac{b}{a}$ .

    6.  so at last we get the value as $[(b + \sqrt{b^{2}-a^{2} } )/a]$ .

              NOTE: please follow the brackets and also understand "Ф" this symbol as "Theta".