Question

if cos theta = a/b find the value of sin theta​

Answer 1

sinθ = √b² - a²/b

Step-by-step explanation:

cosθ = a/b

sin²θ + cos²θ = 1

sin²θ + (a/b)² = 1

sin²θ = 1/1 - a²/b²

sin²θ = b² - a² /b²

$sinθ = \sqrt{ \frac{ {b}^{2} - {a}^{2} }{ {b}^{2} } } = \frac{ \sqrt{ {b}^{2} - {a}^{2} } }{b}$

sinθ = √b² - a²/b