if cos theta and sin theta are the zeroes of the polynomial mx^{2}+nx+1. Then what is the relation between m and n and if m \neq 0
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mx²+nx+1⇒
sinθ+cosθ=-n/m
=msin²θ+nsinθ+1=0 ---------- eqn 1
mcos²θ+n cosθ+1=0 --------------- eqn 2
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On solving the equations we get:--
m +n(-n/m)+2=0
⇒m-n²/m+2=0
⇒m²-n²+2m=0
⇒m²+2m=n² Ans.
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sinθ+cosθ=-n/m
=msin²θ+nsinθ+1=0 ---------- eqn 1
mcos²θ+n cosθ+1=0 --------------- eqn 2
------------------------------------
On solving the equations we get:--
m +n(-n/m)+2=0
⇒m-n²/m+2=0
⇒m²-n²+2m=0
⇒m²+2m=n² Ans.
I hope u got it what u want ! !
plz mark as the best if u liked it ! !
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