Question

if cos theta equal to √3 - 1 by 2√2 and sin theta eqaul to √3+1 by 2√2 then find the value of theta​

Answer 1

Answer:

cos∅=√3-1/2√2

sin∅=√3+1/2√2

tan∅= sin∅/cos∅

tan∅=(√3+1/2√2)/(√3-1/2√2)

tan∅=√3+1/√3-1

thus,by rationalization method

tan∅=(√3+1×√3+1)/(√3-1×√3+1)

tan∅=(3+√3+√3+1)/(3+1)

tan∅=(4+2√3)/(4)

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