Math, asked by sreenath878, 7 months ago

If cos theta equals to b by whole root a square + b square then prove that b + whole root a square + b square by a whole square equals to whole root a square + b square + b divided by whole root a square + b square minus b equals to 1 + cos theta by 1 - cos theta

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Answered by Satyajeet403q

0

can you write it numerically

Answered by rajivdani20p3mkqi

5

Step-by-step explanation:

Hope it helps Sorry for bad quality

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