if cos theta is equals to 12 upon 37 then find sin theta
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since sinA=perpendicular/hypoteneuse=12/37 and cosA=base/ hypoteneuse,
now we need base
for a right angled triangle we know,hyp2=base2 +per2
=base=√(372)-(122) =35,so
cosA=35/37
MARK ME AS A BRAINLIEST
now we need base
for a right angled triangle we know,hyp2=base2 +per2
=base=√(372)-(122) =35,so
cosA=35/37
MARK ME AS A BRAINLIEST
Answered by
2
Answer :-
since sinA=perpendicular/hypoteneuse=12/37 and cosA=base/ hypoteneuse,
now we need base
for a right angled triangle we know,hyp2=base2 +per2
=base=√(372)-(122) =35,so
cosA=35/37
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