If cos theta = m .Find sin theta
Answers
Answered by
0
Answer
Correct option is
D
m
2
+n
2
Given : acosθ+bsinθ=m ---( 1 )
asinθ−bcosθ=n ---( 2 )
Squaring (1) and (2), we get
a
2
cos
2
θ+b
2
sin
2
θ+2absinθcosθ=m
2
---(3)
and
a
2
sin
2
θ+b
2
cos
2
θ−2absinθcosθ=n
2
---(4)
Adding (3) and (4)
a
2
(sin
2
θ+cos
2
θ)+b
2
(sin
2
θ+cos
2
θ)=m
2
+n
2
or
a
2
+b
2
=m
2
+n
2
Answered by
1
Answer:
sinθ = √1 - m²
Step-by-step explanation:
cosθ = m
squaring on both sides,
cos²θ = m²
by identity sin²θ + cos²θ = 1,
sin²θ + m² = 1,
∴ sin²θ = 1 - m²
sinθ = √1 - m² [sin theta = root(1 - m²)]
Hope that helps
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