if cos theta =p/q,then show that√p^2-q^2 cos theat=p
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Step-by-step explanation:
Refer to the attachment!
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llBrandedCrushll
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Step-by-step explanation:
psinθ+qcosθpsinθ−qcosθ=ptanθ+qptanθ−q, on dividing by cosθ
p(p/q)+qp(p/q)−q=p2+q2p2−q2 (∵tanθ=qp)
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