if cos theta =q/√p²+q² prove that [√p²+q²/p+q/p = √p²+q² +q/√p²+q² -q
PLS HELP ME I WILL MARK HIM BRAINSLIST BUT DO IN A GREAT MANNER SO WE UNDERSTAND
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Step-by-step explanation:
in a quadrilateral ABCD the diagonal b is equals to 8.2 cm and the perpendiculars from a and c to it are 3.4 cm and 2.6 cm respectively
find the area of quadrilateral
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