Question

If cos theta = root 10 , then cot theta=? find.​

Answer 1

Answer:

cotQ=√10/-3

Step-by-step explanation:

Hope it will help you

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Answer 2

Answer:

$\cos\theta = \sqrt{10} \\ = > \cos ^{2} \theta = 10 \\ = > 1 - \sin {}^{2} \theta = 10 \\ = > \sin{}^{2} \theta = 1 - 10 = - 9$

we know,

$\cot \theta = \frac{ \cos \theta}{ \sin \theta } \\ = > \cot^{2} \theta = \frac{ \cos{}^{2} \theta}{sin {}^{2} \theta } = \frac{10}{ - 9} \\ = > \cot \theta = \sqrt{ \frac{10}{ - 9} }$