Question

if cos theta + sec theta = 2 then cos^2022 theta + cos^2022 theta =
Pls genuine answers only

Answer 1

Answer:

2

Step-by-step explanation:

Say, theta = x

So, cos(x) + sec(x) = 2

=> cos(x) + 1/cos(x) = 2

=> cos^2 (x) + 1 = 2*cos(x)

=> cos^2 (x) - 2*cos(x) + 1 = 0

=> (cos(x)-1)^2 = 0

=> cos(x) - 1 = 0

=> cos(x) = 1

So, sec(x) = 1 also.

So, cos^2022 theta + cos^2022 theta = 1+1 = 2