Question

if cos theta+sec theta=2 then the value of cos^(8)theta+sin^(8)theta is

Answer 1

Answer:

The correct answer of this question is 1.

Step-by-step explanation:

Given - cos theta + sec theta = 2

To Find  - find the value of cos^(8)theta+sin^(8)theta is

Where x and y are the coordinates of the point on the angle's terminal side, cosine theta equals x, sine theta = y, and tangent theta equals y over x,

cosθ + secθ = 2

cosθ + 1/cosθ = 2

$cos^(2)$θ + 1 = 2cosθ

$cos^(2)$ θ − 2cosθ + 1 = 0

cosθ = − (−2) ± (−2) 2 − 4(1)(1)  / √2 (1)

So,  cosθ = 1

$cos^(8)$θ + $sin^(8)$ θ

= $1^8$ + 0

= 1

#SPJ3

Answer 2

Answer:

cos^(8) θ + sin^(8)θ=1

Step-by-step explanation:

Given:

cosθ + secθ = 2

Then

cosθ + 1/cosθ = 2

cos^(2)θ + 1 = 2cosθ

cos^(2)θ 2cosθ + 1 = 0

cosθ = − (−2) ± (−2) 2 − 4(1)(1) / √2 *1

So, cosθ = 1

cos^(8 )θ + sin^(8)θ

= 1^8 + 0

= 1

The project code is #SPJ2