Question

if cos theta + sec theta = 4 then the value of cos ² theta + sec² theta​

Answer 1

Step-by-step explanation:

$\cos \alpha + \sec\alpha = 4 \\ { \cos }^{2} \alpha + { \sec }^{2} \alpha = 16$

Answer 2

Answer:

here given cosθ+secθ=4...(i)

Step-by-step explanation:

on squaring eqn. i both side, we get

cos²θ+sec²θ+2×cosθ×secθ=16

=>cos²θ+sec²θ+2=16

=>cos²θ+sec²θ=14.

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