If cos theta + sin theta = 1 then prove that cos theta - sin theta = ±1
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Step-by-step explanation:
Given
cosθ+sinθ=1
(cosθ+sinθ)
2
=1
2
cos
2
θ+sin
2
θ+2sinθcosθ=1
1+2sinθcosθ=1
2sinθcosθ=0
sinθcosθ=0
Now (cosθ−sinθ)
2
=(cosθ+sinθ)
2
−4sinθcosθ
=1
2
−4×0
=1
(cosθ−sinθ)
2
=1
cosθ−sinθ=±1
∴ Hence proved.
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