Question

If cos thita=2mn+2n^2/m^2+2mn+2n^2 then prove that tan thita=m^2+2mn/2mn+2n^2​

Answer 1

Answer:

ANSWER

sinθ=

m

2

+2mn+2n

2

m

2

+2mn

Constant a right triangle

ABC is a right triangle

(m

2

+2mn+2n

2

)

2

=(m

2

+2mn)

2

+x

2

(m

2

+2mn+2n

2

)

2

−(m

2

+2mn)

2

+x

2

<a

2

−b

2

=(a+b)(a−b)

(m

2

+2mn+2n

2

+m

2

+2mn)(m

2

+2mn+2n

2

−m

2

+2mn)=x

2

(2m

2

+4mn+2a

2

)(2n

2

)=x

2

2

(m

2

+2mn+n

2

)

(2n

2

)=x

2

2(m+n)

2

2n

2

=x

2

4n

2

(m+n)

2

=x

2

x=

4n

2

(m+n)

2

=2n(m+n)

=2mn+2n

2

tanθ=

2mn+2n

2

m

2

+2mn