if cos thita = 3/5 ,the value of sin2 thita will be ___ ( 3/5 ,24/25,5/3)
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[Note : Here, '∆' represents 'theta']
Cos ∆ = ⅗
We know that :-
Sin²∆ + Cos²∆ = 1
Sin²∆ = 1 - Cos²∆
Sin²∆ = 1 - ⅗
Sin²∆ = (5-3)/5
Sin²∆ = ⅖.
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