Math, asked by AalekhJaiswal, 8 months ago

if cos thita+ sec thita=2,find the value of Cos¹¹thita+Sec¹¹thita​

Answers

Answered by nakulathul
0

Answer:

pls brainliest

Cos theta+sec theta =2

=> cos ^2 theta +1 = 2 cos theta

=> cos^2 theta -2 cos theta +1=0

Solving the above quadratic equation in cos theta,we get

cos theta =1

=>theta =cos inverse (1)

=>theta=2 n pi

Now we need to find the value of

cos 100 theta+sec 100 theta

Substitute the value of theta as theta=2 n pi:

=>cos 100 theta + sec 100 theta = cos 100 (2 n pi) + sec 100 (2 n pi)

=cos 2 (100n pi) + sec 2 (100n pi)

Let 100n=k , some variable

=>cos 100 theta + sec 100 theta = cos (2 k pi) + sec (2 k pi) = 1 + 1 = 2

Step-by-step explanation:

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