Question

if (cos thita+sec thita=2) then find the value of (cos¹¹thita+sec¹¹thita) =?.?​

Answer 1

Answer:

Hi your answer is as follows

Step-by-step explanation:

Here it is given that ,

cos + sec = 2

$cos+\frac{1}{cos} = 2$

in the above case we can see that cos and it's reciprocal add up to 2

so therefore we conclude that cos and sec both of them are 1

Therefore ,

$cos^{11} + sec^{11} = 2$

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Alter:

Cos theta+sec theta =2

=> cos ^2 theta +1 = 2 cos theta

=> cos^2 theta -2 cos theta +1=0

Solving the above quadratic equation in cos theta,we get

cos theta =1

=>theta =cos inverse (1)

=>theta=2 n pi

Now we need to find the value of

cos 100 theta+sec 100 theta

Substitute the value of theta as theta=2 n pi:

=>cos 100 theta + sec 100 theta = cos 100 (2 n pi) + sec 100 (2 n pi)

=cos 2 (100n pi) + sec 2 (100n pi)

Let 100n=k , some variable

=>cos 100 theta + sec 100 theta = cos (2 k pi) + sec (2 k pi) = 1 + 1 = 2

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Hope it helps,

Mark as brainliest if you are satisfied with my answer

Answer 2

XD means

, Closed eye and open mouth

laughing is called as XD.

example: X D

X is on the space of eye and D is on the. space of open mouth.

X

D

X