Question

if cos tita =0.6 show that 5 sin tita - 3 tan tita = 0​

Answer 1

Step-by-step explanation:

Given:

$cos \theta \: = 0.6 \\ \because \: {sin}^{2} \theta \: = 1 - {cos}^{2} \theta \\ = 1 - (0.6) \\ = 1 - 0.36 \\ {sin}^{2} \theta \: = 0.64 \\ \therefore \: {sin}\theta \: = \sqrt{0.64} \\ \therefore \: {sin}\theta \: = 0.8 \\ tan \theta \: = \frac{{sin}\theta }{{cos}\theta } = \frac{0.8}{0.6} = \frac{4}{3} \\ now \\ 5{sin}\theta - 3{tan}\theta \\ = 5 \times 0.8 - 3 \times \frac{4}{3} \\ = 4 \: \\ = 0 \\ thus \: \\ 5{sin}\theta - 3{tan}\theta = 0 \\ hence \: proved.$