if cos tita =√2 find the value 2sin²tita + cos²tita/sin tita+ costita
qais:
value of cos tita lies between -1 to 1 and √2 is greater than 1...so plz recheck ur question
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By using formula cos²α + sin²α = 1
as cosα = √2 therefore (√2)² + sin²α = 1
sinα = 1
putting the values of sin and cos in the eqn
2 x (1)² + (√2)²/1 + √2 = 2 + 2 +√2 = 4√2 Ans.
as cosα = √2 therefore (√2)² + sin²α = 1
sinα = 1
putting the values of sin and cos in the eqn
2 x (1)² + (√2)²/1 + √2 = 2 + 2 +√2 = 4√2 Ans.
when u solve this.... (√2)² + sin²α = 1 ....sin²α = (-1) ...which cant be possible
ok
square hai toh minus plus ho jyegaa
samajgai
kon??
sarfaraz
its right na??
value of cos tita lies between -1 to 1 and √2 is greater than 1...so plz recheck the question
ok
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