if cos tita =root 3 upon 2, find the other trigonometric ratios of angle tita. I don't know where is root and tita sign in keyboard so I wrote in alphabets.
Answers
Answered by
7
let theta =@
according to question ,
cos@=root3/2
we know
cos@ =base/hypotenus =b/h
hence ,
p=+_root {2^2-(root3)^2}=+_1
now,
sin@=p/h =+_1/2
tan@=p/b =+_1/root3
sec@ =1/cos@ =2/root3
cosec@ =1/sin@=+_2
according to question ,
cos@=root3/2
we know
cos@ =base/hypotenus =b/h
hence ,
p=+_root {2^2-(root3)^2}=+_1
now,
sin@=p/h =+_1/2
tan@=p/b =+_1/root3
sec@ =1/cos@ =2/root3
cosec@ =1/sin@=+_2
Answered by
3
Let ß be the angle ,given
cos ß=√3 /2
ß= cos inverse √3 /2
ß= 30°
sin ß=sin 30= 1/2
tan ß= tan 30=1 /√3
cosec ß=cosec 30=2
cot ß=cot 30=√3
sec ß=sec 30= 2/√3
cos ß=√3 /2
ß= cos inverse √3 /2
ß= 30°
sin ß=sin 30= 1/2
tan ß= tan 30=1 /√3
cosec ß=cosec 30=2
cot ß=cot 30=√3
sec ß=sec 30= 2/√3
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