Question

if cos x= -0.6 and π<x<3π/2 then tan (x/4) (a) (1-√5)/2 (b) (√5-1) /2 (c) (√5) /2 (d) (√5+1) /2​

Answer 1

Step-by-step explanation:

:

A)wkt, tanx = perpendicular(p)/base(b) .....(1)

B)We are given tanx=5/12 .....(2)

C)On comparing the quantities we get that p=5 and b=12

D)We require the value of hypotenuse(h),

for this we apply the Pythagoras theorum i.e,

h

2

=

p

2

+

b

2

⇒

h

2

=

5

2

+

12

2

⇒

h

2

=25+144

⇒

h

2

=169

⇒

h=

√

169

⇒

h=13

..............................................................................................................

Hence , sinx = perpendicular/hypotenuse=p/h = 5/13

cosx = base/hypotenuse=b/h = **12/13* .... *(Answer)

.............................................................................................................

I hope this helps :)

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