If cos x = 1 then cos 3x
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cos 3x = 4 cos^3x - 3cosx Here is what I did and where I'm stuck: cos 3x = cos (2x+x) = (cos 2x)(cos x) - (sin 2x)(sin x) = (2 cos^2x-1)(cos x) - [(2 sinx)(cosx)](sinx) I'm not sure how you distribute this.
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