Question

If cos x=a/b then sin X is eqal to

Answer 1

Step-by-step explanation:

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Answer 2

Given:

cos x=a/b

To Find:

Find the value of Sin x

Solution:

Trigonometric functions are the functions of the angles of a triangle, the relation between the side and angle of a triangle is shown using these functions, they are also known as circular functions.

The functions are sine, cosine, tangent, cotangent, secant and cosecant.

The functions can also be expressed as values of the sides of a right-angled triangle,

$sin=\frac{p}{h}\\cos=\frac{b}{h}$

So we can say that if cos x =a/b then 'a' is the base and 'b' is the hypotenuse, now using the Pythagoras theorem we can find the value of p,

$p^2+a^2=b^2\\p=\sqrt{b^2-a^2}$

So the value of sin will be,

$sin x=\frac{p}{h}\\=\frac{\sqrt{b^2-a^2} }{b}$

Hence, the value of sin x is $\frac{\sqrt{b^2-a^2} }{b}$.