Question

if cos x/cos y=2 and cos (x-y) = root 3/2 then tan y

Answer 1

Answer:

cos x/ cos y =2 ,

cos x =2 cos y

cos [x-y] = rt 3/2 then [x-y] =30 , and x= [y+30]

cos x= cos [y+30] = cos y cos 30 - sin y sin 30 = 2 cos y

rt3/2 . cos y - 1/2. sin y = 2 cos y , divide across by siny

[ rt 3/2]/ tan y -[1/2] = 2/tan y , multiply by tan y

rt3/2 -[1/2] tan y =2

tan y =sq rt3 - 4