If cos x + secx = 2, show that cos^8x + sec^8x = 2.
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As we know that
X+1/X=f(X)
where f(X) lies between (-infinite, - 2] or [2,infinite)
So the above function is given like this
X+1/X=2
Here X=cosx so
Cosx=1 this is only possible when x=2npie so x=0 is the solution
So
The value of
Cos^10X+sec^20x=2
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