Math, asked by srishitha14, 6 months ago

if cos0 =24/25 and 0 is acute find the value of sin0, tan0 ,sec0

Answers

Answered by ag0008699

2

Answer:

cos0 =24/25.......given
sin²0 = 1-cos²0=1-(24/25)² =1-576/625

=625-576/625 =49/625

sin0=√49/652=7/25

tan0=sin0/cos0=7/25/24/25=7/24
sec0 =1/cos0=25/24

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