Question

if cos2A=1-tan^2A/1+tan^2A​ then a =​

Answer 1

Answer:

cos2A = cos^2 A - sin^2 A

= cos^2 A ( 1 - tan^2 A)

= (1 - tan^2 A)/sec^2 A

= (1 - tan^2 A)/(1 + tan^2 A)

Step-by-step explanation:

cos2A = cos^2 A - sin^2 A

= cos^2 A ( 1 - tan^2 A)

= (1 - tan^2 A)/sec^2 A

= (1 - tan^2 A)/(1 + tan^2 A)

but this is not a .this is proves