If cos²a + cos² B + cos² y = 3 , then
sin² a + sin² ß + sin² y =
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Given :- cos²a + cos² ß + cos² y = 3
To find :- sin² a + sin² ß + sin² y
Process :-
We know that cos²x + sin²x = 1 (Formula)
We can also write it as cos²x = 1 - sin²x
Then, cos²a + cos² ß + cos² y can be written as:
1- sin²a+1 -sin²ß +1-sin²y = 3
3 - (sin² a + sin² ß + sin² y) = 3
- (sin² a + sin² ß + sin² y) = 0
⋆ sin² a + sin² ß + sin² y = 0 ⋆
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