If cos6θ = a cos6θ + b cos4θsin2θ + c cos2θsin4θ + d sin6θ,
find a, b, c, d.
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Answer:
sin2θ+cos2θ)3=1
sin6θ+cos6θ+3sin2θcos2θ(sin2θ+cos2θ)=1
sin6θ+cos6θ+3sin2θcos2θ(1)=1
Hence answer is C
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