if cos9Q=sinQ,find value of tan5Q
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cos(90-Q)=sinQ
cos9Q=cos(90-Q)
removing cos on both sides
9Q=90-Q
10Q=90
Q=9
tan5Q = tan45
=1
1 is answer
cos9Q=cos(90-Q)
removing cos on both sides
9Q=90-Q
10Q=90
Q=9
tan5Q = tan45
=1
1 is answer
gsnarayana:
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Answered by
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The value of tan5Q is1
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