If cos9x-2cos6x=2,then the generel solution of x is
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Answer:
Step-by-step explanation:
cos6x = 2 (cos3x) ^ 2 - 1
cos9x = 4 (cos3x) ^ 3 - 3 (cos3x).
Cos3x considered t = (| T | =
==> 4T ^ 3 - 4T ^ 2 - 3T + 2 = 2
==> T = 0;
. T = -1/2
. T = 3/2 (by type> 1)
$ * $ With cos 3x = 0 ==> 3x = (Pi) / 2 + k (Pi) ==> x = (Pi) / 6 + k (Pi) / 3
$ * $ With cos 3x = -1/2 ==> 3x = - (P) / 3 + k2 (Pi) ==> x = - (P) / 9 + k2 (Pi) / 3
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