Question

if cos9x= sinx and 9x < 90', then find the value of tan5x.​

Answer 1

Answer:

If cos 9x = sin x, then

sin (90–9x) = sin x, or

90–9x = x, or

90 = 10x, or

x = 9. Check: sin 9 = 0.156434465 = cos 81.

Hence tan 25x = tan 225 = tan (180+45) = [tan 180 + tan 45]/(1 - tan 180 x tan45)

= (0+1)/(1–0*1)

= 1/1

Answer 2

Answer:

+xxx

Explanation:

maja hi majaaaa