if cosA=0.5and cosB=1/√2 find tanA-tanB/1+tanA×tanB please answer I will mark it as a brainliest
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cos A= 0.5 = 1/2 therefore A = 60°
cos B = 1/√2 therefore B = 45°
(tan 60° - tan 45°)/(1 + tan 60° × tan 45°)
=> (√3 - 1)/(1 + √3*1)
=> (√3 - 1)/(√3 + 1)
=> (√3 - 1)²/(√3+1)(√3-1)
[ rationalise the denominator ]
=> ( 3 + 1 - 2√3 )/3 - 1
=> (4 - 2√3)/2
=> 2 - √3
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