Question

if cosA=0.6 show that 5 sinA-3 tanA=0​

Answer 1

Answer:

Step-by-step explanation:

cos A = $\frac{3}{5}$

=>sin A = $\frac{4}{5}$

=>tan A = sin A/cos A =$\frac{\frac{4}{5} }{\frac{3}{5} }$ = 4/3

5 sin A-3 tan A = $5 *\frac{4}{5} -3 * \frac{4}{3}$ =4 - 4 = 0

Answer 2

Answer:

cos A = $\frac{3}{5}$

=>sin A = $\frac{4}{5}$

$>tan A = sin A/cos A =\frac{\frac{4}{5} }{\frac{3}{5} }$

5 sin A-3 tan A = 5 $*\frac{4}{5} - 3* \frac{4}{3}$

=4 - 4 = 0