Question

if cosA=0.6 then find the value of tanA=?​

Answer 1

Answer:

Step-by-step explanation:

cos A=0.6

sec A=1/0.6

tan²A =sec²A-1

=(1/0.6)²-1

=1/0.36(1-0.36)

=0.64/0.36

tan²A=16/9

tan A=4/3

Answer 2

Answer:

CosA=0.6

CosA=6/10=3/5=B/H

Applying Pythagoras theorem;

(H)2=(B)2+(P)2

(5)2=(3)2+(P)2

25=9+(P)2

25-9=(P)2

16=(P)2

√16=P

4=P

NOW,

tanA=P/B=4/3...

Step-by-step explanation:

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