Question

If cosA=0.6 then the value of (5sinA-3tanA) is​

Answer 1

Answer:

hi what is your name I'm new in this app.

Step-by-step explanation:

which class is this question

Answer 2

Step-by-step explanation:

Given, cosθθ = 0.6 =610=35=610=35

Let us draw a triangle ABC in which ∠∠B = 90°.

Let ∠∠A = θθ°.

Then, cosθ=ABAC=35cos⁡θ=ABAC=35

Let AB = 3k and AC = 5k, where k is positive.

By Pythagoras' theorem, we have

AC2 = AB2 + BC2

⇒⇒BC2 = AC2 - AB2

= (5k)2 - (3k)2 = 25k2 - 9k2 = 16k2

⇒BC=16k2−−−−√=4k⇒BC=16k2=4k

sinθ=ABAC=4k5k=45sin⁡θ=ABAC=4k5k=45

cosθ=35cos⁡θ=35

tanθ=sinθcosθ=(45×53)=43tan⁡θ=sin⁡θcos⁡θ=(45×53)=43

⇒(5sinθ−3tanθ)=(5×45−3×43)=0⇒(5sin⁡θ−3tan⁡θ)=(5×45−3×43)=0

Hence, (5sinθθ - 3 tanθθ) = 0.