Question

If cosA=1/2 and sinB=1/√2,find the value of tanA-tanB/1+tanAtanB.Here angle A and B are from same triangles
plzz solve fast​

Answer 1

Answer:

Given tanA = 1/2   and tanB = 1/3

 we know that 

tan(A+B) = (tanA + tanB)/1-tanA*tanB

tan(A+B) = (1/2+1/3)/(1-1/2*1/3)

               =(5/6)/(1-1/6)

             = (5/6)/(5/6)

              =1

tan (A+B)=tan 45                          ( since tan 45 = 1)

therefore A+B= 4

Answer 2

Step-by-step explanation:

Given tanA = 1/2   and tanB = 1/3

 we know that 

tan(A+B) = (tanA + tanB)/1-tanA*tanB

tan(A+B) = (1/2+1/3)/(1-1/2*1/3)

               =(5/6)/(1-1/6)

             = (5/6)/(5/6)

              =1

tan (A+B)=tan 45                          ( since tan 45 = 1)

therefore A+B= 4