Question

If cosa=1/2×cos b=1 then a+b\2× tan a-b/2

Answer 1

:

cosa/cosb = k

(cos b – cos a)/(cos b + cos a) = (1-k) / (1+k)

[sin ((a-b)/2)sin((a+b)/2)]/ [cos ((a-b)/2)cos((a+b)/2)] = (1-k) / (1+k)

[tan ((a-b)/2)tan((a+b)/2)] = (1-k) / (1+k)

tan((a+b)/2) = [(1-k) / (1+k)] cot ((a-b)/2)

hope it helps you out and please mark me as BRAINLIEST

jo in any one

mhf-pfky-qvd