Question

If cosA=1/2,find the value of 2secA/1+tan²A

Answer 1

Answer:

1 is the answer for the given problem

Answer 2

Answer:2secA/1+tan²A=1

Step-by-step explanation:cosa=adjacent /hypotenuse =1/2

cosa =1/2,then seca=1/cosa=1/1/2=2/1=2

by the pythagoras therom,

Side^2+side^2=Hypotenuse ^2

Opposite ^2+1^2=2^2

Opposite^2=4-1

Opposite side=root3

tana=opposite/adjacent =root3/1=root3

2secA/1+tan²A=2×2/1+(root3 )^2=4/1+3=4/4=1