Question

If cosA=12÷13,find the values of sin2A,cos2A and tan2A​

Answer 1

$\sin(2a) = 2 \times \frac{12}{13} \\ \frac{24}{13}$

tan 2a

sin

Answer 2

Answer:

Given,

cosA=12/13=b/h

p^2= (13)^2-(12)^2

= 169-144

= 25

p= 5

Step-by-step explanation:

sin^2A= (p/h)^2

=(5/13)^2= 25/169

cos^2A= (b/h)^2

=(12/13)^2=144/169

tan^2= (p/b)^2

=(5/12)^2=25/144