If cosA=12/13,than find sinA and tanA
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Answer:
perpendicular=p
base=b
hypotenuse=h
cos A=12/13= b/h
by Pythagoras theorem,
h²=p²+b²
13²=p²+12²
p²=169-144
p²=25
p=5
sinA=p/h=5/13
tanA=p/b=5/12
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