Question

if cosA=12/13,then find sinA​

Answer 1

Step-by-step explanation:

given,cosA=12/13

cosA=adjacent to A/hypotenus

let k is the common factor

cosA=12k/13k

(H)²=S²+S²

(13k)²=(12k)²+S²

169k²=144k²+S²

-S²=144k²-169k²

-S²=-25k²

S²=25k²

S=5k

sinA=opposite to A/hypotenus

sinA=5k/13k

sinA=5/13