If CosA=12/13,
then find SinA and
Tan A (A<90)
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Step-by-step explanation:
cosA=12/13
sin^2A+cos^2A=1
sin^2A=1-COs^2A
sin^2A=1-(12/13)^
sin^2A=1-144/169=25/169
sinA=5/13
TanA= sinA/cosA=(5/13)/(12/13)=5/12
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